143310000121 has 2 divisors, whose sum is σ = 143310000122. Its totient is φ = 143310000120.

The previous prime is 143310000109. The next prime is 143310000181. The reversal of 143310000121 is 121000013341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77653624896 + 65656375225 = 278664^2 + 256235^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143310000121 is a prime.

It is a super-2 number, since 2×143310000121² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143310000095 and 143310000104.

It is not a weakly prime, because it can be changed into another prime (143310000101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71655000060 + 71655000061.

It is an arithmetic number, because the mean of its divisors is an integer number (71655000061).

Almost surely, 2^143310000121 is an apocalyptic number.

It is an amenable number.

143310000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

143310000121 is an equidigital number, since it uses as much as digits as its factorization.

143310000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 143310000121 its reverse (121000013341), we get a palindrome (264310013462).

The spelling of 143310000121 in words is "one hundred forty-three billion, three hundred ten million, one hundred twenty-one", and thus it is an aban number.