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143314431223 = 228799626377
BaseRepresentation
bin1000010101111000110…
…1001010110011110111
3111200220211101102122011
42011132031022303313
54322001443244343
6145500541345051
713232315365045
oct2053615126367
9450824342564
10143314431223
11558632953a7
1223937868187
131068c457ac2
146d178c3395
153adbbc529d
hex215e34acf7

143314431223 has 4 divisors (see below), whose sum is σ = 143315286400. Its totient is φ = 143313576048.

The previous prime is 143314431217. The next prime is 143314431389. The reversal of 143314431223 is 322134413341.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 143314431223 - 25 = 143314431191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143314434223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84390 + ... + 541987.

It is an arithmetic number, because the mean of its divisors is an integer number (35828821600).

Almost surely, 2143314431223 is an apocalyptic number.

143314431223 is a deficient number, since it is larger than the sum of its proper divisors (855177).

143314431223 is an equidigital number, since it uses as much as digits as its factorization.

143314431223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 855176.

The product of its digits is 20736, while the sum is 31.

Adding to 143314431223 its reverse (322134413341), we get a palindrome (465448844564).

The spelling of 143314431223 in words is "one hundred forty-three billion, three hundred fourteen million, four hundred thirty-one thousand, two hundred twenty-three".

Divisors: 1 228799 626377 143314431223