Base | Representation |
---|---|
bin | 11010101100011101… |
… | …11010000110000011 |
3 | 1100222210112021102222 |
4 | 31112032322012003 |
5 | 213322400303220 |
6 | 10330041001255 |
7 | 1015103006264 |
oct | 152616720603 |
9 | 40883467388 |
10 | 14331650435 |
11 | 6094930103 |
12 | 293b78322b |
13 | 147523bc3b |
14 | 99d56896b |
15 | 58d2e4e25 |
hex | 3563ba183 |
14331650435 has 4 divisors (see below), whose sum is σ = 17197980528. Its totient is φ = 11465320344.
The previous prime is 14331650423. The next prime is 14331650479. The reversal of 14331650435 is 53405613341.
14331650435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53405613341 = 829 ⋅64421729.
It is a cyclic number.
It is not a de Polignac number, because 14331650435 - 26 = 14331650371 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14331650395 and 14331650404.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1433165039 + ... + 1433165048.
It is an arithmetic number, because the mean of its divisors is an integer number (4299495132).
Almost surely, 214331650435 is an apocalyptic number.
14331650435 is a deficient number, since it is larger than the sum of its proper divisors (2866330093).
14331650435 is an equidigital number, since it uses as much as digits as its factorization.
14331650435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2866330092.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 14331650435 in words is "fourteen billion, three hundred thirty-one million, six hundred fifty thousand, four hundred thirty-five".
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