14332143112241 has 4 divisors (see below), whose sum is σ = 14356069896000. Its totient is φ = 14308216328484.

The previous prime is 14332143112201. The next prime is 14332143112267. The reversal of 14332143112241 is 14221134123341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14332143112241 - 2²² = 14332138917937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14332143112198 and 14332143112207.

It is not an unprimeable number, because it can be changed into a prime (14332143112201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11963390981 + ... + 11963392178.

It is an arithmetic number, because the mean of its divisors is an integer number (3589017474000).

Almost surely, 2^{14332143112241} is an apocalyptic number.

It is an amenable number.

14332143112241 is a deficient number, since it is larger than the sum of its proper divisors (23926783759).

14332143112241 is an equidigital number, since it uses as much as digits as its factorization.

14332143112241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23926783758.

The product of its digits is 13824, while the sum is 32.

Adding to 14332143112241 its reverse (14221134123341), we get a palindrome (28553277235582).

The spelling of 14332143112241 in words is "fourteen trillion, three hundred thirty-two billion, one hundred forty-three million, one hundred twelve thousand, two hundred forty-one".