Base | Representation |
---|---|
bin | 11010101100100011… |
… | …00111010101110011 |
3 | 1100222211212022212001 |
4 | 31112101213111303 |
5 | 213323041010201 |
6 | 10330104114431 |
7 | 1015112023162 |
oct | 152621472563 |
9 | 40884768761 |
10 | 14332360051 |
11 | 6095275269 |
12 | 293ba65a17 |
13 | 1475429c29 |
14 | 99d6b13d9 |
15 | 58d3d5301 |
hex | 356467573 |
14332360051 has 4 divisors (see below), whose sum is σ = 15175440072. Its totient is φ = 13489280032.
The previous prime is 14332360039. The next prime is 14332360067. The reversal of 14332360051 is 15006323341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15006323341 = 56269 ⋅266689.
It is a cyclic number.
It is not a de Polignac number, because 14332360051 - 29 = 14332359539 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14332361051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421539985 + ... + 421540018.
It is an arithmetic number, because the mean of its divisors is an integer number (3793860018).
Almost surely, 214332360051 is an apocalyptic number.
14332360051 is a deficient number, since it is larger than the sum of its proper divisors (843080021).
14332360051 is an equidigital number, since it uses as much as digits as its factorization.
14332360051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 843080020.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 14332360051 its reverse (15006323341), we get a palindrome (29338683392).
The spelling of 14332360051 in words is "fourteen billion, three hundred thirty-two million, three hundred sixty thousand, fifty-one".
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