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14333003134042 = 27166501567021
BaseRepresentation
bin1101000010010010100110…
…0011110111010001011010
31212202012222122001220022111
43100210221203313101122
53334312442300242132
650252253555542534
73006345115316545
oct320445143672132
955665878056274
1014333003134042
114626657676a7a
1217359b98baa4a
137cc79a388828
14377a147d985c
1519cc7ab98647
hexd09298f745a

14333003134042 has 4 divisors (see below), whose sum is σ = 21499504701066. Its totient is φ = 7166501567020.

The previous prime is 14333003134033. The next prime is 14333003134067. The reversal of 14333003134042 is 24043130033341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13573248587721 + 759754546321 = 3684189^2 + 871639^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14333003133995 and 14333003134013.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3583250783509 + ... + 3583250783512.

Almost surely, 214333003134042 is an apocalyptic number.

14333003134042 is a deficient number, since it is larger than the sum of its proper divisors (7166501567024).

14333003134042 is an equidigital number, since it uses as much as digits as its factorization.

14333003134042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7166501567023.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 14333003134042 its reverse (24043130033341), we get a palindrome (38376133167383).

The spelling of 14333003134042 in words is "fourteen trillion, three hundred thirty-three billion, three million, one hundred thirty-four thousand, forty-two".

Divisors: 1 2 7166501567021 14333003134042