Base | Representation |
---|---|
bin | 100000100101110010010100… |
… | …101011011011001000111010 |
3 | 200210111121110212112122011112 |
4 | 200211302110223123020322 |
5 | 122241341311102412214 |
6 | 1224502443555000322 |
7 | 42122356453221662 |
oct | 4045622453331072 |
9 | 623447425478145 |
10 | 143334143013434 |
11 | 4174173a02159a |
12 | 140ab14a5990a2 |
13 | 61c9475879819 |
14 | 27575a3ab11a2 |
15 | 11886b3adca3e |
hex | 825c94adb23a |
143334143013434 has 4 divisors (see below), whose sum is σ = 215001214520154. Its totient is φ = 71667071506716.
The previous prime is 143334143013337. The next prime is 143334143013487. The reversal of 143334143013434 is 434310341433341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 124456447560025 + 18877695453409 = 11156005^2 + 4344847^2 .
It is a super-3 number, since 3×1433341430134343 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143334143013391 and 143334143013400.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35833535753357 + ... + 35833535753360.
Almost surely, 2143334143013434 is an apocalyptic number.
143334143013434 is a deficient number, since it is larger than the sum of its proper divisors (71667071506720).
143334143013434 is an equidigital number, since it uses as much as digits as its factorization.
143334143013434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71667071506719.
The product of its (nonzero) digits is 746496, while the sum is 41.
Adding to 143334143013434 its reverse (434310341433341), we get a palindrome (577644484446775).
The spelling of 143334143013434 in words is "one hundred forty-three trillion, three hundred thirty-four billion, one hundred forty-three million, thirteen thousand, four hundred thirty-four".
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