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14340113405434 = 27170056702717
BaseRepresentation
bin1101000010101101000101…
…0111011001010111111010
31212202220100011022010000101
43100223101113121113322
53334422023012433214
650255431313430014
73010016243531005
oct320532127312772
955686304263011
1014340113405434
114629676198123
121737262b6b30a
138003614904cb
143780cac5c53c
1519d044ee5774
hexd0ad15d95fa

14340113405434 has 4 divisors (see below), whose sum is σ = 21510170108154. Its totient is φ = 7170056702716.

The previous prime is 14340113405413. The next prime is 14340113405531. The reversal of 14340113405434 is 43450431104341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12663256751209 + 1676856654225 = 3558547^2 + 1294935^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14340113405393 and 14340113405402.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3585028351357 + ... + 3585028351360.

Almost surely, 214340113405434 is an apocalyptic number.

14340113405434 is a deficient number, since it is larger than the sum of its proper divisors (7170056702720).

14340113405434 is an equidigital number, since it uses as much as digits as its factorization.

14340113405434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7170056702719.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 14340113405434 its reverse (43450431104341), we get a palindrome (57790544509775).

The spelling of 14340113405434 in words is "fourteen trillion, three hundred forty billion, one hundred thirteen million, four hundred five thousand, four hundred thirty-four".

Divisors: 1 2 7170056702717 14340113405434