Base | Representation |
---|---|
bin | 1101000010101101000101… |
… | …0111011001010111111010 |
3 | 1212202220100011022010000101 |
4 | 3100223101113121113322 |
5 | 3334422023012433214 |
6 | 50255431313430014 |
7 | 3010016243531005 |
oct | 320532127312772 |
9 | 55686304263011 |
10 | 14340113405434 |
11 | 4629676198123 |
12 | 1737262b6b30a |
13 | 8003614904cb |
14 | 3780cac5c53c |
15 | 19d044ee5774 |
hex | d0ad15d95fa |
14340113405434 has 4 divisors (see below), whose sum is σ = 21510170108154. Its totient is φ = 7170056702716.
The previous prime is 14340113405413. The next prime is 14340113405531. The reversal of 14340113405434 is 43450431104341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12663256751209 + 1676856654225 = 3558547^2 + 1294935^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14340113405393 and 14340113405402.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3585028351357 + ... + 3585028351360.
Almost surely, 214340113405434 is an apocalyptic number.
14340113405434 is a deficient number, since it is larger than the sum of its proper divisors (7170056702720).
14340113405434 is an equidigital number, since it uses as much as digits as its factorization.
14340113405434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7170056702719.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 14340113405434 its reverse (43450431104341), we get a palindrome (57790544509775).
The spelling of 14340113405434 in words is "fourteen trillion, three hundred forty billion, one hundred thirteen million, four hundred five thousand, four hundred thirty-four".
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