Base | Representation |
---|---|
bin | 10100110111100010011… |
… | …001110011000111010111 |
3 | 12002002110111101001112022 |
4 | 110313202121303013113 |
5 | 141443334231221401 |
6 | 3014440355243355 |
7 | 205414262221145 |
oct | 24674231630727 |
9 | 5062414331468 |
10 | 1434022523351 |
11 | 503190369690 |
12 | 1b1b0b2a955b |
13 | a52c64784b2 |
14 | 4d59ad8c595 |
15 | 2747eeac71b |
hex | 14de26731d7 |
1434022523351 has 16 divisors (see below), whose sum is σ = 1584319355520. Its totient is φ = 1287132081120.
The previous prime is 1434022523347. The next prime is 1434022523357. The reversal of 1434022523351 is 1533252204341.
It is a cyclic number.
It is not a de Polignac number, because 1434022523351 - 22 = 1434022523347 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434022523357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1773785 + ... + 2452418.
It is an arithmetic number, because the mean of its divisors is an integer number (99019959720).
Almost surely, 21434022523351 is an apocalyptic number.
1434022523351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1434022523351 is a deficient number, since it is larger than the sum of its proper divisors (150296832169).
1434022523351 is a wasteful number, since it uses less digits than its factorization.
1434022523351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4226606.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 1434022523351 its reverse (1533252204341), we get a palindrome (2967274727692).
The spelling of 1434022523351 in words is "one trillion, four hundred thirty-four billion, twenty-two million, five hundred twenty-three thousand, three hundred fifty-one".
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