Base | Representation |
---|---|
bin | 1101000010101101100110… |
… | …1101000110000110110011 |
3 | 1212202220200220120001221020 |
4 | 3100223121231012012303 |
5 | 3334422314321431121 |
6 | 50255453232230523 |
7 | 3010022562650106 |
oct | 320533155060663 |
9 | 55686626501836 |
10 | 14340253311411 |
11 | 46297381655a5 |
12 | 17372a199b443 |
13 | 800384466b01 |
14 | 37810167a73d |
15 | 19d05242e1c6 |
hex | d0ad9b461b3 |
14340253311411 has 12 divisors (see below), whose sum is σ = 19124178485832. Its totient is φ = 9558248890944.
The previous prime is 14340253311347. The next prime is 14340253311421. The reversal of 14340253311411 is 11411335204341.
It is a happy number.
14340253311411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14340253311411 - 26 = 14340253311347 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14340253311421) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 78521275 + ... + 78703691.
It is an arithmetic number, because the mean of its divisors is an integer number (1593681540486).
Almost surely, 214340253311411 is an apocalyptic number.
14340253311411 is a deficient number, since it is larger than the sum of its proper divisors (4783925174421).
14340253311411 is an frugal number, since it uses more digits than its factorization.
14340253311411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192658 (or 187539 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 14340253311411 its reverse (11411335204341), we get a palindrome (25751588515752).
The spelling of 14340253311411 in words is "fourteen trillion, three hundred forty billion, two hundred fifty-three million, three hundred eleven thousand, four hundred eleven".
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