Base | Representation |
---|---|
bin | 10100110111100011100… |
… | …000010011000110010001 |
3 | 12002002111210010222210211 |
4 | 110313203200103012101 |
5 | 141443403444120213 |
6 | 3014442255324121 |
7 | 205414605262642 |
oct | 24674340230621 |
9 | 5062453128724 |
10 | 1434041004433 |
11 | 50319a841804 |
12 | 1b1b15520641 |
13 | a52ca24944b |
14 | 4d59d5dd6c9 |
15 | 2748190d53d |
hex | 14de3813191 |
1434041004433 has 8 divisors (see below), whose sum is σ = 1459049574656. Its totient is φ = 1409177412000.
The previous prime is 1434041004421. The next prime is 1434041004437. The reversal of 1434041004433 is 3344001404341.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1434041004433 - 217 = 1434040873361 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1434041004395 and 1434041004404.
It is not an unprimeable number, because it can be changed into a prime (1434041004437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36224493 + ... + 36264058.
It is an arithmetic number, because the mean of its divisors is an integer number (182381196832).
Almost surely, 21434041004433 is an apocalyptic number.
It is an amenable number.
1434041004433 is a deficient number, since it is larger than the sum of its proper divisors (25008570223).
1434041004433 is an equidigital number, since it uses as much as digits as its factorization.
1434041004433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72488895.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1434041004433 its reverse (3344001404341), we get a palindrome (4778042408774).
The spelling of 1434041004433 in words is "one trillion, four hundred thirty-four billion, forty-one million, four thousand, four hundred thirty-three".
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