Base | Representation |
---|---|
bin | 10100110111100111101… |
… | …100001010111011000111 |
3 | 12002002200200021121001200 |
4 | 110313213230022323013 |
5 | 141444024433204133 |
6 | 3014453244353543 |
7 | 205416420200133 |
oct | 24674754127307 |
9 | 5062620247050 |
10 | 1434111225543 |
11 | 503226443987 |
12 | 1b1b34b458b3 |
13 | a530b9647b9 |
14 | 4d5a8a7c3c3 |
15 | 27487b7e913 |
hex | 14de7b0aec7 |
1434111225543 has 6 divisors (see below), whose sum is σ = 2071493992464. Its totient is φ = 956074150356.
The previous prime is 1434111225541. The next prime is 1434111225559. The reversal of 1434111225543 is 3455221114341.
1434111225543 is a `hidden beast` number, since 1 + 43 + 41 + 1 + 1 + 22 + 554 + 3 = 666.
It is not a de Polignac number, because 1434111225543 - 21 = 1434111225541 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1434111225498 and 1434111225507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434111225541) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 79672845855 + ... + 79672845872.
It is an arithmetic number, because the mean of its divisors is an integer number (345248998744).
Almost surely, 21434111225543 is an apocalyptic number.
1434111225543 is a deficient number, since it is larger than the sum of its proper divisors (637382766921).
1434111225543 is a wasteful number, since it uses less digits than its factorization.
1434111225543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159345691733 (or 159345691730 counting only the distinct ones).
The product of its digits is 57600, while the sum is 36.
Adding to 1434111225543 its reverse (3455221114341), we get a palindrome (4889332339884).
The spelling of 1434111225543 in words is "one trillion, four hundred thirty-four billion, one hundred eleven million, two hundred twenty-five thousand, five hundred forty-three".
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