Search a number
-
+
1434121200403 = 3124945893347
BaseRepresentation
bin10100110111101000010…
…010001110001100010011
312002002201101001100222221
4110313220102032030103
5141444040011403103
63014454242241511
7205416601033303
oct24675022161423
95062641040887
101434121200403
11503231037171
121b1b38356297
13a5310a47a98
144d5aa117603
15274889a01bd
hex14de848e313

1434121200403 has 4 divisors (see below), whose sum is σ = 1434167125000. Its totient is φ = 1434075275808.

The previous prime is 1434121200367. The next prime is 1434121200409. The reversal of 1434121200403 is 3040021214341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1434121200403 - 225 = 1434087645971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1434121200409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22915425 + ... + 22977922.

It is an arithmetic number, because the mean of its divisors is an integer number (358541781250).

Almost surely, 21434121200403 is an apocalyptic number.

1434121200403 is a deficient number, since it is larger than the sum of its proper divisors (45924597).

1434121200403 is an equidigital number, since it uses as much as digits as its factorization.

1434121200403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45924596.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1434121200403 its reverse (3040021214341), we get a palindrome (4474142414744).

The spelling of 1434121200403 in words is "one trillion, four hundred thirty-four billion, one hundred twenty-one million, two hundred thousand, four hundred three".

Divisors: 1 31249 45893347 1434121200403