14341252013101 has 4 divisors (see below), whose sum is σ = 15444425244892. Its totient is φ = 13238078781312.

The previous prime is 14341252013041. The next prime is 14341252013113. The reversal of 14341252013101 is 10131025214341.

14341252013101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5120494648201 + 9220757364900 = 2262851^2 + 3036570^2 .

It is a cyclic number.

It is not a de Polignac number, because 14341252013101 - 2⁹ = 14341252012589 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14341252013101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14341252013201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551586615876 + ... + 551586615901.

It is an arithmetic number, because the mean of its divisors is an integer number (3861106311223).

Almost surely, 2^{14341252013101} is an apocalyptic number.

It is an amenable number.

14341252013101 is a deficient number, since it is larger than the sum of its proper divisors (1103173231791).

14341252013101 is a wasteful number, since it uses less digits than its factorization.

14341252013101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1103173231790.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 14341252013101 its reverse (10131025214341), we get a palindrome (24472277227442).

The spelling of 14341252013101 in words is "fourteen trillion, three hundred forty-one billion, two hundred fifty-two million, thirteen thousand, one hundred one".