143413211131 has 4 divisors (see below), whose sum is σ = 151849282392. Its totient is φ = 134977139872.

The previous prime is 143413211129. The next prime is 143413211153. The reversal of 143413211131 is 131112314341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143413211131 - 2¹ = 143413211129 is a prime.

It is a super-2 number, since 2×143413211131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143413211096 and 143413211105.

It is not an unprimeable number, because it can be changed into a prime (143413211101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4218035605 + ... + 4218035638.

It is an arithmetic number, because the mean of its divisors is an integer number (37962320598).

Almost surely, 2^143413211131 is an apocalyptic number.

143413211131 is a deficient number, since it is larger than the sum of its proper divisors (8436071261).

143413211131 is an equidigital number, since it uses as much as digits as its factorization.

143413211131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8436071260.

The product of its digits is 864, while the sum is 25.

Adding to 143413211131 its reverse (131112314341), we get a palindrome (274525525472).

The spelling of 143413211131 in words is "one hundred forty-three billion, four hundred thirteen million, two hundred eleven thousand, one hundred thirty-one".