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1434141143111 = 41143924307889
BaseRepresentation
bin10100110111101001011…
…110010011000001000111
312002002202202120120020202
4110313221132103001013
5141444110113034421
63014500233521115
7205420232403305
oct24675136230107
95062682516222
101434141143111
11503241318446
121b1b42b7319b
13a5314c0b0c1
144d5aca29275
152748a5de10b
hex14de9793047

1434141143111 has 8 divisors (see below), whose sum is σ = 1470141187200. Its totient is φ = 1398189717760.

The previous prime is 1434141143069. The next prime is 1434141143117. The reversal of 1434141143111 is 1113411414341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1434141143111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434141143117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12094946 + ... + 12212943.

It is an arithmetic number, because the mean of its divisors is an integer number (183767648400).

Almost surely, 21434141143111 is an apocalyptic number.

1434141143111 is a deficient number, since it is larger than the sum of its proper divisors (36000044089).

1434141143111 is a wasteful number, since it uses less digits than its factorization.

1434141143111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24309369.

The product of its digits is 2304, while the sum is 29.

Adding to 1434141143111 its reverse (1113411414341), we get a palindrome (2547552557452).

The spelling of 1434141143111 in words is "one trillion, four hundred thirty-four billion, one hundred forty-one million, one hundred forty-three thousand, one hundred eleven".

Divisors: 1 41 1439 58999 24307889 996623449 34979052271 1434141143111