Base | Representation |
---|---|
bin | 11010101101110000… |
… | …10110011101100111 |
3 | 1101000112222020012001 |
4 | 31112320112131213 |
5 | 213333140431120 |
6 | 10331105510131 |
7 | 1015264235116 |
oct | 152670263547 |
9 | 41015866161 |
10 | 14342514535 |
11 | 609aa804a8 |
12 | 2943342347 |
13 | 1477573bbb |
14 | 9a0b95c7d |
15 | 58e23de0a |
hex | 356e16767 |
14342514535 has 4 divisors (see below), whose sum is σ = 17211017448. Its totient is φ = 11474011624.
The previous prime is 14342514533. The next prime is 14342514539. The reversal of 14342514535 is 53541524341.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53541524341 = 7121 ⋅7518821.
It is a cyclic number.
It is not a de Polignac number, because 14342514535 - 21 = 14342514533 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14342514494 and 14342514503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14342514533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434251449 + ... + 1434251458.
It is an arithmetic number, because the mean of its divisors is an integer number (4302754362).
Almost surely, 214342514535 is an apocalyptic number.
14342514535 is a deficient number, since it is larger than the sum of its proper divisors (2868502913).
14342514535 is an equidigital number, since it uses as much as digits as its factorization.
14342514535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2868502912.
The product of its digits is 144000, while the sum is 37.
The spelling of 14342514535 in words is "fourteen billion, three hundred forty-two million, five hundred fourteen thousand, five hundred thirty-five".
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