14342557016113 has 4 divisors (see below), whose sum is σ = 14344390407168. Its totient is φ = 14340723625060.

The previous prime is 14342557016101. The next prime is 14342557016131. The reversal of 14342557016113 is 31161075524341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14342557016113 - 2²¹ = 14342554918961 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14342557016113.

It is not an unprimeable number, because it can be changed into a prime (14342557016153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 916683793 + ... + 916699438.

It is an arithmetic number, because the mean of its divisors is an integer number (3586097601792).

Almost surely, 2^{14342557016113} is an apocalyptic number.

It is an amenable number.

14342557016113 is a deficient number, since it is larger than the sum of its proper divisors (1833391055).

14342557016113 is an equidigital number, since it uses as much as digits as its factorization.

14342557016113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1833391054.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 14342557016113 in words is "fourteen trillion, three hundred forty-two billion, five hundred fifty-seven million, sixteen thousand, one hundred thirteen".