Base | Representation |
---|---|
bin | 11010101101110100… |
… | …01110010000010001 |
3 | 1101000120220011020212 |
4 | 31112322032100101 |
5 | 213333302131301 |
6 | 10331124213505 |
7 | 1015301350460 |
oct | 152672162021 |
9 | 41016804225 |
10 | 14343005201 |
11 | 60a0286108 |
12 | 294353a295 |
13 | 14776b6335 |
14 | 9a0c829d7 |
15 | 58e2d94bb |
hex | 356e8e411 |
14343005201 has 16 divisors (see below), whose sum is σ = 16645216896. Its totient is φ = 12105386496.
The previous prime is 14343005191. The next prime is 14343005221. The reversal of 14343005201 is 10250034341.
It is a de Polignac number, because none of the positive numbers 2k-14343005201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14343005221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80150 + ... + 187376.
It is an arithmetic number, because the mean of its divisors is an integer number (1040326056).
Almost surely, 214343005201 is an apocalyptic number.
It is an amenable number.
14343005201 is a deficient number, since it is larger than the sum of its proper divisors (2302211695).
14343005201 is a wasteful number, since it uses less digits than its factorization.
14343005201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107528.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 14343005201 its reverse (10250034341), we get a palindrome (24593039542).
The spelling of 14343005201 in words is "fourteen billion, three hundred forty-three million, five thousand, two hundred one".
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