Base | Representation |
---|---|
bin | 10100110111110011100… |
… | …010100100000010001111 |
3 | 12002010012112101002101020 |
4 | 110313303202210002033 |
5 | 141444431332033201 |
6 | 3014525105445223 |
7 | 205424353061253 |
oct | 24676342440217 |
9 | 5063175332336 |
10 | 1434310033551 |
11 | 50331869231a |
12 | 1b1b8b640813 |
13 | a5340bc2385 |
14 | 4d5c7230263 |
15 | 2749a350a36 |
hex | 14df38a408f |
1434310033551 has 8 divisors (see below), whose sum is σ = 1912502916480. Its totient is φ = 956161919832.
The previous prime is 1434310033549. The next prime is 1434310033567. The reversal of 1434310033551 is 1553300134341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1434310033551 - 21 = 1434310033549 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434310035551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11117475 + ... + 11245748.
It is an arithmetic number, because the mean of its divisors is an integer number (239062864560).
Almost surely, 21434310033551 is an apocalyptic number.
1434310033551 is a deficient number, since it is larger than the sum of its proper divisors (478192882929).
1434310033551 is a wasteful number, since it uses less digits than its factorization.
1434310033551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22384605.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1434310033551 its reverse (1553300134341), we get a palindrome (2987610167892).
The spelling of 1434310033551 in words is "one trillion, four hundred thirty-four billion, three hundred ten million, thirty-three thousand, five hundred fifty-one".
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