Base | Representation |
---|---|
bin | 11010101101110101… |
… | …01010110011011101 |
3 | 1101000121010002122222 |
4 | 31112322222303131 |
5 | 213333314402031 |
6 | 10331130515125 |
7 | 1015302345425 |
oct | 152672526335 |
9 | 41017102588 |
10 | 14343122141 |
11 | 60a0355a57 |
12 | 2943595aa5 |
13 | 147772762a |
14 | 9a0cb3485 |
15 | 58e30de7b |
hex | 356eaacdd |
14343122141 has 4 divisors (see below), whose sum is σ = 14348470752. Its totient is φ = 14337773532.
The previous prime is 14343122137. The next prime is 14343122147. The reversal of 14343122141 is 14122134341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14343122141 - 22 = 14343122137 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14343122141.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14343122147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2670281 + ... + 2675646.
It is an arithmetic number, because the mean of its divisors is an integer number (3587117688).
Almost surely, 214343122141 is an apocalyptic number.
It is an amenable number.
14343122141 is a deficient number, since it is larger than the sum of its proper divisors (5348611).
14343122141 is an equidigital number, since it uses as much as digits as its factorization.
14343122141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5348610.
The product of its digits is 2304, while the sum is 26.
Adding to 14343122141 its reverse (14122134341), we get a palindrome (28465256482).
The spelling of 14343122141 in words is "fourteen billion, three hundred forty-three million, one hundred twenty-two thousand, one hundred forty-one".
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