Base | Representation |
---|---|
bin | 1101000010111000010111… |
… | …1001110100111101111010 |
3 | 1212210012011020202102201101 |
4 | 3100232011321310331322 |
5 | 3334444223414031414 |
6 | 50301052034042014 |
7 | 3010154303133364 |
oct | 320560571647572 |
9 | 55705136672641 |
10 | 14343142330234 |
11 | 462a98aa14163 |
12 | 173796941930a |
13 | 800724b614c3 |
14 | 3782d7233d34 |
15 | 19d170d9ea74 |
hex | d0b85e74f7a |
14343142330234 has 4 divisors (see below), whose sum is σ = 21514713495354. Its totient is φ = 7171571165116.
The previous prime is 14343142330141. The next prime is 14343142330249. The reversal of 14343142330234 is 43203324134341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11500596910009 + 2842545420225 = 3391253^2 + 1685985^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14343142330193 and 14343142330202.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3585785582557 + ... + 3585785582560.
Almost surely, 214343142330234 is an apocalyptic number.
14343142330234 is a deficient number, since it is larger than the sum of its proper divisors (7171571165120).
14343142330234 is an equidigital number, since it uses as much as digits as its factorization.
14343142330234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7171571165119.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 14343142330234 its reverse (43203324134341), we get a palindrome (57546466464575).
The spelling of 14343142330234 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty-two million, three hundred thirty thousand, two hundred thirty-four".
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