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14343142330234 = 27171571165117
BaseRepresentation
bin1101000010111000010111…
…1001110100111101111010
31212210012011020202102201101
43100232011321310331322
53334444223414031414
650301052034042014
73010154303133364
oct320560571647572
955705136672641
1014343142330234
11462a98aa14163
12173796941930a
13800724b614c3
143782d7233d34
1519d170d9ea74
hexd0b85e74f7a

14343142330234 has 4 divisors (see below), whose sum is σ = 21514713495354. Its totient is φ = 7171571165116.

The previous prime is 14343142330141. The next prime is 14343142330249. The reversal of 14343142330234 is 43203324134341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11500596910009 + 2842545420225 = 3391253^2 + 1685985^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14343142330193 and 14343142330202.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3585785582557 + ... + 3585785582560.

Almost surely, 214343142330234 is an apocalyptic number.

14343142330234 is a deficient number, since it is larger than the sum of its proper divisors (7171571165120).

14343142330234 is an equidigital number, since it uses as much as digits as its factorization.

14343142330234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7171571165119.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 14343142330234 its reverse (43203324134341), we get a palindrome (57546466464575).

The spelling of 14343142330234 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty-two million, three hundred thirty thousand, two hundred thirty-four".

Divisors: 1 2 7171571165117 14343142330234