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14343411431 = 67321312647
BaseRepresentation
bin11010101101110111…
…10001011011100111
31101000121122210111102
431112323301123213
5213333403131211
610331141030315
71015304662016
oct152673613347
941017583442
1014343411431
1160a0533338
1229436b539b
1314777c91cb
149a0d4aa7d
1558e369a3b
hex356ef16e7

14343411431 has 4 divisors (see below), whose sum is σ = 14364724752. Its totient is φ = 14322098112.

The previous prime is 14343411403. The next prime is 14343411451. The reversal of 14343411431 is 13411434341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14343411431 - 26 = 14343411367 is a prime.

It is a super-2 number, since 2×143434114312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14343411394 and 14343411403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14343411451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10655651 + ... + 10656996.

It is an arithmetic number, because the mean of its divisors is an integer number (3591181188).

Almost surely, 214343411431 is an apocalyptic number.

14343411431 is a deficient number, since it is larger than the sum of its proper divisors (21313321).

14343411431 is an equidigital number, since it uses as much as digits as its factorization.

14343411431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21313320.

The product of its digits is 6912, while the sum is 29.

Adding to 14343411431 its reverse (13411434341), we get a palindrome (27754845772).

The spelling of 14343411431 in words is "fourteen billion, three hundred forty-three million, four hundred eleven thousand, four hundred thirty-one".

Divisors: 1 673 21312647 14343411431