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1434410034311 = 5692520931519
BaseRepresentation
bin10100110111111001100…
…000000010010010000111
312002010110111112122122002
4110313321200002102013
5142000132432044221
63014543041055515
7205430006055542
oct24677140022207
95063414478562
101434410034311
1150336a084381
121b1bb902759b
13a5358836317
144d5d6621859
15274a400580b
hex14df9802487

1434410034311 has 4 divisors (see below), whose sum is σ = 1436930966400. Its totient is φ = 1431889102224.

The previous prime is 1434410034289. The next prime is 1434410034329. The reversal of 1434410034311 is 1134300144341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1434410034311 - 214 = 1434410017927 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434410034371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1260465191 + ... + 1260466328.

It is an arithmetic number, because the mean of its divisors is an integer number (359232741600).

Almost surely, 21434410034311 is an apocalyptic number.

1434410034311 is a deficient number, since it is larger than the sum of its proper divisors (2520932089).

1434410034311 is an equidigital number, since it uses as much as digits as its factorization.

1434410034311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2520932088.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1434410034311 its reverse (1134300144341), we get a palindrome (2568710178652).

The spelling of 1434410034311 in words is "one trillion, four hundred thirty-four billion, four hundred ten million, thirty-four thousand, three hundred eleven".

Divisors: 1 569 2520931519 1434410034311