1434411412431 has 4 divisors (see below), whose sum is σ = 1912548549912. Its totient is φ = 956274274952.

The previous prime is 1434411412397. The next prime is 1434411412433. The reversal of 1434411412431 is 1342141144341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1434411412431 - 2¹⁵ = 1434411379663 is a prime.

It is a super-2 number, since 2×1434411412431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1434411412392 and 1434411412401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434411412433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239068568736 + ... + 239068568741.

It is an arithmetic number, because the mean of its divisors is an integer number (478137137478).

Almost surely, 2^{1434411412431} is an apocalyptic number.

1434411412431 is a deficient number, since it is larger than the sum of its proper divisors (478137137481).

1434411412431 is an equidigital number, since it uses as much as digits as its factorization.

1434411412431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478137137480.

The product of its digits is 18432, while the sum is 33.

Adding to 1434411412431 its reverse (1342141144341), we get a palindrome (2776552556772).

The spelling of 1434411412431 in words is "one trillion, four hundred thirty-four billion, four hundred eleven million, four hundred twelve thousand, four hundred thirty-one".