1434421414121 has 4 divisors (see below), whose sum is σ = 1440423177600. Its totient is φ = 1428419650644.

The previous prime is 1434421414117. The next prime is 1434421414147. The reversal of 1434421414121 is 1214141244341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1434421414121 - 2² = 1434421414117 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1434421414171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3000881381 + ... + 3000881858.

It is an arithmetic number, because the mean of its divisors is an integer number (360105794400).

Almost surely, 2^{1434421414121} is an apocalyptic number.

It is an amenable number.

1434421414121 is a deficient number, since it is larger than the sum of its proper divisors (6001763479).

1434421414121 is an equidigital number, since it uses as much as digits as its factorization.

1434421414121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6001763478.

The product of its digits is 12288, while the sum is 32.

Adding to 1434421414121 its reverse (1214141244341), we get a palindrome (2648562658462).

The spelling of 1434421414121 in words is "one trillion, four hundred thirty-four billion, four hundred twenty-one million, four hundred fourteen thousand, one hundred twenty-one".