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1434442100001 = 3478147366667
BaseRepresentation
bin10100110111111011011…
…010010110110100100001
312002010112201212202111020
4110313323122112310201
5142000214134200001
63014550144240053
7205430545446531
oct24677332266441
95063481782436
101434442100001
11503386195849
121b2007910029
13a53623825c1
144d5da9ab4c1
15274a6c3b736
hex14dfb696d21

1434442100001 has 4 divisors (see below), whose sum is σ = 1912589466672. Its totient is φ = 956294733332.

The previous prime is 1434442099963. The next prime is 1434442100009. The reversal of 1434442100001 is 1000012444341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1434442100001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1434442100009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239073683331 + ... + 239073683336.

It is an arithmetic number, because the mean of its divisors is an integer number (478147366668).

Almost surely, 21434442100001 is an apocalyptic number.

It is an amenable number.

1434442100001 is a deficient number, since it is larger than the sum of its proper divisors (478147366671).

1434442100001 is an equidigital number, since it uses as much as digits as its factorization.

1434442100001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478147366670.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 1434442100001 its reverse (1000012444341), we get a palindrome (2434454544342).

The spelling of 1434442100001 in words is "one trillion, four hundred thirty-four billion, four hundred forty-two million, one hundred thousand, one".

Divisors: 1 3 478147366667 1434442100001