Base | Representation |
---|---|
bin | 11010101110000100… |
… | …10000111101011101 |
3 | 1101000201212021012200 |
4 | 31113002100331131 |
5 | 213334322112222 |
6 | 10331241322113 |
7 | 1015325311104 |
oct | 152702207535 |
9 | 41021767180 |
10 | 14345113437 |
11 | 60a1496056 |
12 | 2944196339 |
13 | 1477c73b05 |
14 | 9a127103b |
15 | 58e5a3eac |
hex | 357090f5d |
14345113437 has 6 divisors (see below), whose sum is σ = 20720719422. Its totient is φ = 9563408952.
The previous prime is 14345113381. The next prime is 14345113469. The reversal of 14345113437 is 73431154341.
14345113437 is a `hidden beast` number, since 1 + 43 + 451 + 134 + 37 = 666.
It can be written as a sum of positive squares in only one way, i.e., 13519643076 + 825470361 = 116274^2 + 28731^2 .
It is not a de Polignac number, because 14345113437 - 210 = 14345112413 is a prime.
It is a super-3 number, since 3×143451134373 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14345113477) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 796950738 + ... + 796950755.
It is an arithmetic number, because the mean of its divisors is an integer number (3453453237).
Almost surely, 214345113437 is an apocalyptic number.
It is an amenable number.
14345113437 is a deficient number, since it is larger than the sum of its proper divisors (6375605985).
14345113437 is a wasteful number, since it uses less digits than its factorization.
14345113437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1593901499 (or 1593901496 counting only the distinct ones).
The product of its digits is 60480, while the sum is 36.
Adding to 14345113437 its reverse (73431154341), we get a palindrome (87776267778).
The spelling of 14345113437 in words is "fourteen billion, three hundred forty-five million, one hundred thirteen thousand, four hundred thirty-seven".
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