14350115533 has 4 divisors (see below), whose sum is σ = 15453970588. Its totient is φ = 13246260480.

The previous prime is 14350115509. The next prime is 14350115537. The reversal of 14350115533 is 33551105341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33551105341 = 13 ⋅2580854257.

It can be written as a sum of positive squares in 2 ways, for example, as 1851322729 + 12498792804 = 43027^2 + 111798^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14350115533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14350115495 and 14350115504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14350115537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551927508 + ... + 551927533.

It is an arithmetic number, because the mean of its divisors is an integer number (3863492647).

Almost surely, 2^14350115533 is an apocalyptic number.

14350115533 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14350115533 is a deficient number, since it is larger than the sum of its proper divisors (1103855055).

14350115533 is a wasteful number, since it uses less digits than its factorization.

14350115533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1103855054.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 14350115533 in words is "fourteen billion, three hundred fifty million, one hundred fifteen thousand, five hundred thirty-three".