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14351413201 = 23623974487
BaseRepresentation
bin11010101110110100…
…10010111111010001
31101001011201022212021
431113122102333101
5213342430210301
610332024331441
71015432666546
oct152732227721
941034638767
1014351413201
1160a4aa9174
122946313b81
13147936b398
149a2030bcd
1558edea8a1
hex357692fd1

14351413201 has 4 divisors (see below), whose sum is σ = 14975387712. Its totient is φ = 13727438692.

The previous prime is 14351413187. The next prime is 14351413207. The reversal of 14351413201 is 10231415341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14351413201 - 219 = 14350888913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14351413207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311987221 + ... + 311987266.

It is an arithmetic number, because the mean of its divisors is an integer number (3743846928).

Almost surely, 214351413201 is an apocalyptic number.

It is an amenable number.

14351413201 is a deficient number, since it is larger than the sum of its proper divisors (623974511).

14351413201 is an equidigital number, since it uses as much as digits as its factorization.

14351413201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 623974510.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 14351413201 its reverse (10231415341), we get a palindrome (24582828542).

The spelling of 14351413201 in words is "fourteen billion, three hundred fifty-one million, four hundred thirteen thousand, two hundred one".

Divisors: 1 23 623974487 14351413201