Base | Representation |
---|---|
bin | 10100111000100101000… |
… | …101101101100001101011 |
3 | 12002012100110121101011112 |
4 | 110320211011231201223 |
5 | 142003132140043201 |
6 | 3015143403220535 |
7 | 205454066016161 |
oct | 24704505554153 |
9 | 5065313541145 |
10 | 1435141331051 |
11 | 50370495a44a |
12 | 1b2181b1774b |
13 | a54441b299c |
14 | 4d6657c5231 |
15 | 274e830b0bb |
hex | 14e2516d86b |
1435141331051 has 4 divisors (see below), whose sum is σ = 1435251714072. Its totient is φ = 1435030948032.
The previous prime is 1435141331047. The next prime is 1435141331081. The reversal of 1435141331051 is 1501331415341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1435141331051 - 22 = 1435141331047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1435141330999 and 1435141331017.
It is not an unprimeable number, because it can be changed into a prime (1435141331081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55172006 + ... + 55198011.
It is an arithmetic number, because the mean of its divisors is an integer number (358812928518).
Almost surely, 21435141331051 is an apocalyptic number.
1435141331051 is a deficient number, since it is larger than the sum of its proper divisors (110383021).
1435141331051 is a wasteful number, since it uses less digits than its factorization.
1435141331051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110383020.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 1435141331051 its reverse (1501331415341), we get a palindrome (2936472746392).
The spelling of 1435141331051 in words is "one trillion, four hundred thirty-five billion, one hundred forty-one million, three hundred thirty-one thousand, fifty-one".
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