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143522020641 = 376519625213
BaseRepresentation
bin1000010110101010010…
…1000011110100100001
3111201110022000001210010
42011222211003310201
54322413114130031
6145533314555133
713240416022026
oct2055245036441
9451408001703
10143522020641
115595a4913aa
1223995298aa9
13106c346b68c
146d372bd54d
153b0002d246
hex216a943d21

143522020641 has 8 divisors (see below), whose sum is σ = 191365501120. Its totient is φ = 95679943632.

The previous prime is 143522020633. The next prime is 143522020643. The reversal of 143522020641 is 146020225341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 143522020641 - 23 = 143522020633 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143522020599 and 143522020608.

It is not an unprimeable number, because it can be changed into a prime (143522020643) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83050 + ... + 542163.

It is an arithmetic number, because the mean of its divisors is an integer number (23920687640).

Almost surely, 2143522020641 is an apocalyptic number.

It is an amenable number.

143522020641 is a deficient number, since it is larger than the sum of its proper divisors (47843480479).

143522020641 is an equidigital number, since it uses as much as digits as its factorization.

143522020641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 701735.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 143522020641 its reverse (146020225341), we get a palindrome (289542245982).

The spelling of 143522020641 in words is "one hundred forty-three billion, five hundred twenty-two million, twenty thousand, six hundred forty-one".

Divisors: 1 3 76519 229557 625213 1875639 47840673547 143522020641