14352321153 has 4 divisors (see below), whose sum is σ = 19136428208. Its totient is φ = 9568214100.

The previous prime is 14352321121. The next prime is 14352321161. The reversal of 14352321153 is 35112325341.

14352321153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35112325341 = 3 ⋅11704108447.

It is not a de Polignac number, because 14352321153 - 2⁵ = 14352321121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14352321153.

It is not an unprimeable number, because it can be changed into a prime (14352321353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2392053523 + ... + 2392053528.

It is an arithmetic number, because the mean of its divisors is an integer number (4784107052).

Almost surely, 2^14352321153 is an apocalyptic number.

It is an amenable number.

14352321153 is a deficient number, since it is larger than the sum of its proper divisors (4784107055).

14352321153 is an equidigital number, since it uses as much as digits as its factorization.

14352321153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4784107054.

The product of its digits is 10800, while the sum is 30.

Adding to 14352321153 its reverse (35112325341), we get a palindrome (49464646494).

The spelling of 14352321153 in words is "fourteen billion, three hundred fifty-two million, three hundred twenty-one thousand, one hundred fifty-three".