14356053231113 has 4 divisors (see below), whose sum is σ = 15661148979408. Its totient is φ = 13050957482820.

The previous prime is 14356053231101. The next prime is 14356053231127. The reversal of 14356053231113 is 31113235065341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14356053231113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14356053231413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652547874131 + ... + 652547874152.

It is an arithmetic number, because the mean of its divisors is an integer number (3915287244852).

Almost surely, 2^{14356053231113} is an apocalyptic number.

It is an amenable number.

14356053231113 is a deficient number, since it is larger than the sum of its proper divisors (1305095748295).

14356053231113 is a wasteful number, since it uses less digits than its factorization.

14356053231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1305095748294.

The product of its (nonzero) digits is 97200, while the sum is 38.

Adding to 14356053231113 its reverse (31113235065341), we get a palindrome (45469288296454).

The spelling of 14356053231113 in words is "fourteen trillion, three hundred fifty-six billion, fifty-three million, two hundred thirty-one thousand, one hundred thirteen".