143631245252041 has 4 divisors (see below), whose sum is σ = 144948963098500. Its totient is φ = 142313527405584.

The previous prime is 143631245252039. The next prime is 143631245252059. The reversal of 143631245252041 is 140252542136341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 82866429610000 + 60764815642041 = 9103100^2 + 7795179^2 .

It is a cyclic number.

It is not a de Polignac number, because 143631245252041 - 2¹ = 143631245252039 is a prime.

It is a super-2 number, since 2×143631245252041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143631245252081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658858923066 + ... + 658858923283.

It is an arithmetic number, because the mean of its divisors is an integer number (36237240774625).

Almost surely, 2^{143631245252041} is an apocalyptic number.

It is an amenable number.

143631245252041 is a deficient number, since it is larger than the sum of its proper divisors (1317717846459).

143631245252041 is a wasteful number, since it uses less digits than its factorization.

143631245252041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1317717846458.

The product of its (nonzero) digits is 691200, while the sum is 43.

Adding to 143631245252041 its reverse (140252542136341), we get a palindrome (283883787388382).

The spelling of 143631245252041 in words is "one hundred forty-three trillion, six hundred thirty-one billion, two hundred forty-five million, two hundred fifty-two thousand, forty-one".