Base | Representation |
---|---|
bin | 10100111100100100001… |
… | …101110011010001111101 |
3 | 12002121101202202200202020 |
4 | 110330210031303101331 |
5 | 142040413420014403 |
6 | 3021132225150353 |
7 | 205665132036336 |
oct | 24744415632175 |
9 | 5077352680666 |
10 | 1439421641853 |
11 | 505500a9a298 |
12 | 1b2b7748b3b9 |
13 | a5976bca380 |
14 | 4d95006528d |
15 | 27698ea1453 |
hex | 14f2437347d |
1439421641853 has 16 divisors (see below), whose sum is σ = 2066887749696. Its totient is φ = 885786831360.
The previous prime is 1439421641773. The next prime is 1439421641869. The reversal of 1439421641853 is 3581461249341.
It is not a de Polignac number, because 1439421641853 - 234 = 1422241772669 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1439421641796 and 1439421641805.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1439421641153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3817338 + ... + 4177428.
It is an arithmetic number, because the mean of its divisors is an integer number (129180484356).
Almost surely, 21439421641853 is an apocalyptic number.
1439421641853 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1439421641853 is a deficient number, since it is larger than the sum of its proper divisors (627466107843).
1439421641853 is a wasteful number, since it uses less digits than its factorization.
1439421641853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462604.
The product of its digits is 2488320, while the sum is 51.
The spelling of 1439421641853 in words is "one trillion, four hundred thirty-nine billion, four hundred twenty-one million, six hundred forty-one thousand, eight hundred fifty-three".
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