14394553147303 has 4 divisors (see below), whose sum is σ = 16450917882640. Its totient is φ = 12338188411968.

The previous prime is 14394553147301. The next prime is 14394553147333. The reversal of 14394553147303 is 30374135549341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14394553147303 - 2¹ = 14394553147301 is a prime.

It is a super-3 number, since 3×14394553147303³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14394553147301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1028182367658 + ... + 1028182367671.

It is an arithmetic number, because the mean of its divisors is an integer number (4112729470660).

Almost surely, 2^{14394553147303} is an apocalyptic number.

14394553147303 is a deficient number, since it is larger than the sum of its proper divisors (2056364735337).

14394553147303 is an equidigital number, since it uses as much as digits as its factorization.

14394553147303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2056364735336.

The product of its (nonzero) digits is 8164800, while the sum is 52.

The spelling of 14394553147303 in words is "fourteen trillion, three hundred ninety-four billion, five hundred fifty-three million, one hundred forty-seven thousand, three hundred three".