14400033350113 has 8 divisors (see below), whose sum is σ = 14409686513376. Its totient is φ = 14390380680000.

The previous prime is 14400033350041. The next prime is 14400033350161. The reversal of 14400033350113 is 31105333000441.

14400033350113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14400033350113 - 2¹⁷ = 14400033219041 is a prime.

It is a super-4 number, since 4×14400033350113⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14400030350113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72536238 + ... + 72734488.

It is an arithmetic number, because the mean of its divisors is an integer number (1801210814172).

Almost surely, 2^{14400033350113} is an apocalyptic number.

It is an amenable number.

14400033350113 is a deficient number, since it is larger than the sum of its proper divisors (9653163263).

14400033350113 is a wasteful number, since it uses less digits than its factorization.

14400033350113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246575.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 14400033350113 its reverse (31105333000441), we get a palindrome (45505366350554).

The spelling of 14400033350113 in words is "fourteen trillion, four hundred billion, thirty-three million, three hundred fifty thousand, one hundred thirteen".