14400042050533 has 4 divisors (see below), whose sum is σ = 14411758928940. Its totient is φ = 14388325172128.

The previous prime is 14400042050521. The next prime is 14400042050573. The reversal of 14400042050533 is 33505024000441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14276744857764 + 123297192769 = 3778458^2 + 351137^2 .

It is a cyclic number.

It is not a de Polignac number, because 14400042050533 - 2⁵ = 14400042050501 is a prime.

It is a super-2 number, since 2×14400042050533² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14400042050495 and 14400042050504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14400042050573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5858437360 + ... + 5858439817.

It is an arithmetic number, because the mean of its divisors is an integer number (3602939732235).

Almost surely, 2^{14400042050533} is an apocalyptic number.

It is an amenable number.

14400042050533 is a deficient number, since it is larger than the sum of its proper divisors (11716878407).

14400042050533 is a wasteful number, since it uses less digits than its factorization.

14400042050533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11716878406.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 14400042050533 its reverse (33505024000441), we get a palindrome (47905066050974).

The spelling of 14400042050533 in words is "fourteen trillion, four hundred billion, forty-two million, fifty thousand, five hundred thirty-three".