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144002300114 = 272001150057
BaseRepresentation
bin1000011000011100110…
…1001011100011010010
3111202200202201210100202
42012013031023203102
54324404042100424
6150053113015202
713255340232521
oct2060715134322
9452622653322
10144002300114
11560865a9492
1223aaa0b4502
131076bb0a60a
146d80dc04b8
153b2c29d2ae
hex218734b8d2

144002300114 has 4 divisors (see below), whose sum is σ = 216003450174. Its totient is φ = 72001150056.

The previous prime is 144002300077. The next prime is 144002300119. The reversal of 144002300114 is 411003200441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 109789509025 + 34212791089 = 331345^2 + 184967^2 .

It is a super-3 number, since 3×1440023001143 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (144002300119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36000575027 + ... + 36000575030.

Almost surely, 2144002300114 is an apocalyptic number.

144002300114 is a deficient number, since it is larger than the sum of its proper divisors (72001150060).

144002300114 is an equidigital number, since it uses as much as digits as its factorization.

144002300114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72001150059.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 144002300114 its reverse (411003200441), we get a palindrome (555005500555).

The spelling of 144002300114 in words is "one hundred forty-four billion, two million, three hundred thousand, one hundred fourteen".

Divisors: 1 2 72001150057 144002300114