Base | Representation |
---|---|
bin | 100000101111101001001000… |
… | …001010010111000101101010 |
3 | 200212220100202112200101121101 |
4 | 200233221020022113011222 |
5 | 122333440434303013232 |
6 | 1230141541524432014 |
7 | 42222325221443545 |
oct | 4057511012270552 |
9 | 625810675611541 |
10 | 144011464110442 |
11 | 41982a12134755 |
12 | 1419a477b4860a |
13 | 62482b8630c26 |
14 | 277c298dcd85c |
15 | 119b106b601e7 |
hex | 82fa4829716a |
144011464110442 has 4 divisors (see below), whose sum is σ = 216017196165666. Its totient is φ = 72005732055220.
The previous prime is 144011464110373. The next prime is 144011464110497. The reversal of 144011464110442 is 244011464110441.
144011464110442 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 143093295789921 + 918168320521 = 11962161^2 + 958211^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36002866027609 + ... + 36002866027612.
Almost surely, 2144011464110442 is an apocalyptic number.
144011464110442 is a deficient number, since it is larger than the sum of its proper divisors (72005732055224).
144011464110442 is an equidigital number, since it uses as much as digits as its factorization.
144011464110442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72005732055223.
The product of its (nonzero) digits is 49152, while the sum is 37.
Subtracting 144011464110442 from its reverse (244011464110441), we obtain a palindrome (99999999999999).
The spelling of 144011464110442 in words is "one hundred forty-four trillion, eleven billion, four hundred sixty-four million, one hundred ten thousand, four hundred forty-two".
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