14401151100541 has 4 divisors (see below), whose sum is σ = 14497803121500. Its totient is φ = 14304499079584.

The previous prime is 14401151100527. The next prime is 14401151100563. The reversal of 14401151100541 is 14500115110441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8661513872025 + 5739637228516 = 2943045^2 + 2395754^2 .

It is a cyclic number.

It is not a de Polignac number, because 14401151100541 - 2¹¹ = 14401151098493 is a prime.

It is a super-2 number, since 2×14401151100541² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14401151100341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48326010256 + ... + 48326010553.

It is an arithmetic number, because the mean of its divisors is an integer number (3624450780375).

Almost surely, 2^{14401151100541} is an apocalyptic number.

It is an amenable number.

14401151100541 is a deficient number, since it is larger than the sum of its proper divisors (96652020959).

14401151100541 is an equidigital number, since it uses as much as digits as its factorization.

14401151100541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96652020958.

The product of its (nonzero) digits is 1600, while the sum is 28.

Adding to 14401151100541 its reverse (14500115110441), we get a palindrome (28901266210982).

The spelling of 14401151100541 in words is "fourteen trillion, four hundred one billion, one hundred fifty-one million, one hundred thousand, five hundred forty-one".