14401244203 has 4 divisors (see below), whose sum is σ = 14401514880. Its totient is φ = 14400973528.

The previous prime is 14401244201. The next prime is 14401244213. The reversal of 14401244203 is 30244210441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14401244203 - 2¹ = 14401244201 is a prime.

It is a super-2 number, since 2×14401244203² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14401244201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26188 + ... + 171721.

It is an arithmetic number, because the mean of its divisors is an integer number (3600378720).

Almost surely, 2^14401244203 is an apocalyptic number.

14401244203 is a deficient number, since it is larger than the sum of its proper divisors (270677).

14401244203 is an equidigital number, since it uses as much as digits as its factorization.

14401244203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 270676.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 14401244203 its reverse (30244210441), we get a palindrome (44645454644).

The spelling of 14401244203 in words is "fourteen billion, four hundred one million, two hundred forty-four thousand, two hundred three".