1440125325031 has 4 divisors (see below), whose sum is σ = 1442090026072. Its totient is φ = 1438160623992.

The previous prime is 1440125324999. The next prime is 1440125325053. The reversal of 1440125325031 is 1305235210441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1440125325031 - 2⁵ = 1440125324999 is a prime.

It is a super-2 number, since 2×1440125325031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1440125324984 and 1440125325002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1440125325091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 982349421 + ... + 982350886.

It is an arithmetic number, because the mean of its divisors is an integer number (360522506518).

Almost surely, 2^{1440125325031} is an apocalyptic number.

1440125325031 is a deficient number, since it is larger than the sum of its proper divisors (1964701041).

1440125325031 is an equidigital number, since it uses as much as digits as its factorization.

1440125325031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1964701040.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 1440125325031 in words is "one trillion, four hundred forty billion, one hundred twenty-five million, three hundred twenty-five thousand, thirty-one".