Base | Representation |
---|---|
bin | 10100111101001110100… |
… | …000010101000101110011 |
3 | 12002200020012211000222120 |
4 | 110331032200111011303 |
5 | 142043342033021003 |
6 | 3021330452205323 |
7 | 206021535506031 |
oct | 24751640250563 |
9 | 5080205730876 |
10 | 1440131142003 |
11 | 505835538254 |
12 | 1b3135009843 |
13 | a5a5abb4948 |
14 | 4d9ba393551 |
15 | 276db3ed853 |
hex | 14f4e815173 |
1440131142003 has 4 divisors (see below), whose sum is σ = 1920174856008. Its totient is φ = 960087428000.
The previous prime is 1440131141947. The next prime is 1440131142007. The reversal of 1440131142003 is 3002411310441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1440131142003 - 213 = 1440131133811 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1440131142007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240021856998 + ... + 240021857003.
It is an arithmetic number, because the mean of its divisors is an integer number (480043714002).
Almost surely, 21440131142003 is an apocalyptic number.
1440131142003 is a deficient number, since it is larger than the sum of its proper divisors (480043714005).
1440131142003 is an equidigital number, since it uses as much as digits as its factorization.
1440131142003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 480043714004.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1440131142003 its reverse (3002411310441), we get a palindrome (4442542452444).
The spelling of 1440131142003 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, one hundred forty-two thousand, three".
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