1440202214133 has 12 divisors (see below), whose sum is σ = 2170739569440. Its totient is φ = 918389817576.

The previous prime is 1440202214119. The next prime is 1440202214137. The reversal of 1440202214133 is 3314122020441.

1440202214133 is a `hidden beast` number, since 1 + 4 + 4 + 0 + 20 + 221 + 413 + 3 = 666.

It is not a de Polignac number, because 1440202214133 - 2²² = 1440198019829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1440202214097 and 1440202214106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1440202214137) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3478749103 + ... + 3478749516.

It is an arithmetic number, because the mean of its divisors is an integer number (180894964120).

Almost surely, 2^{1440202214133} is an apocalyptic number.

It is an amenable number.

1440202214133 is a deficient number, since it is larger than the sum of its proper divisors (730537355307).

1440202214133 is a wasteful number, since it uses less digits than its factorization.

1440202214133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6957498648 (or 6957498645 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 1440202214133 its reverse (3314122020441), we get a palindrome (4754324234574).

The spelling of 1440202214133 in words is "one trillion, four hundred forty billion, two hundred two million, two hundred fourteen thousand, one hundred thirty-three".