Base | Representation |
---|---|
bin | 1000011000100001010… |
… | …0111010001110111111 |
3 | 111202202002010002211100 |
4 | 2012020110322032333 |
5 | 4324423400303201 |
6 | 150055024024143 |
7 | 13255656116163 |
oct | 2061024721677 |
9 | 452662102740 |
10 | 144021103551 |
11 | 56096181816 |
12 | 23ab4462053 |
13 | 10772992200 |
14 | 6d836b6ca3 |
15 | 3b2dc64886 |
hex | 218853a3bf |
144021103551 has 18 divisors (see below), whose sum is σ = 225263779728. Its totient is φ = 88628370480.
The previous prime is 144021103531. The next prime is 144021103601. The reversal of 144021103551 is 155301120441.
144021103551 is a `hidden beast` number, since 1 + 4 + 4 + 0 + 2 + 1 + 103 + 551 = 666.
144021103551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 144021103551 - 26 = 144021103487 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144021103511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 47342695 + ... + 47345736.
Almost surely, 2144021103551 is an apocalyptic number.
144021103551 is a deficient number, since it is larger than the sum of its proper divisors (81242676177).
144021103551 is a wasteful number, since it uses less digits than its factorization.
144021103551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94688463 (or 94688447 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 144021103551 its reverse (155301120441), we get a palindrome (299322223992).
The spelling of 144021103551 in words is "one hundred forty-four billion, twenty-one million, one hundred three thousand, five hundred fifty-one".
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