Base | Representation |
---|---|
bin | 1101000110010100110001… |
… | …0001100101011001101111 |
3 | 1212222211212101210112212220 |
4 | 3101211030101211121233 |
5 | 3341431410041142201 |
6 | 50344154431530423 |
7 | 3014350354536036 |
oct | 321451421453157 |
9 | 55884771715786 |
10 | 14402305021551 |
11 | 4652a8a798877 |
12 | 174731a989a13 |
13 | 806192ca4c65 |
14 | 37b10a80971d |
15 | 19e984d5b036 |
hex | d194c46566f |
14402305021551 has 8 divisors (see below), whose sum is σ = 19203093110064. Its totient is φ = 9601526807040.
The previous prime is 14402305021537. The next prime is 14402305021567. The reversal of 14402305021551 is 15512050320441.
14402305021551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14402305021551 - 25 = 14402305021519 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14402305021751) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2191825 + ... + 5797301.
It is an arithmetic number, because the mean of its divisors is an integer number (2400386638758).
Almost surely, 214402305021551 is an apocalyptic number.
14402305021551 is a deficient number, since it is larger than the sum of its proper divisors (4800788088513).
14402305021551 is a wasteful number, since it uses less digits than its factorization.
14402305021551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4937001.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 14402305021551 its reverse (15512050320441), we get a palindrome (29914355341992).
The spelling of 14402305021551 in words is "fourteen trillion, four hundred two billion, three hundred five million, twenty-one thousand, five hundred fifty-one".
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