Search a number
-
+
14402312325521 = 20756369387667
BaseRepresentation
bin1101000110010100110010…
…1101011100100110010001
31212222211212220112122001022
43101211030231130212101
53341431413423404041
650344155252245225
73014350503606311
oct321451455344621
955884786478038
1014402312325521
114652a9392740a
121747321310815
13806194661633
1437b10b78b441
1519e98580024b
hexd194cb5c991

14402312325521 has 4 divisors (see below), whose sum is σ = 14402381920752. Its totient is φ = 14402242730292.

The previous prime is 14402312325503. The next prime is 14402312325559. The reversal of 14402312325521 is 12552321320441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14402312325521 - 222 = 14402308131217 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14402312325581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34486271 + ... + 34901396.

It is an arithmetic number, because the mean of its divisors is an integer number (3600595480188).

Almost surely, 214402312325521 is an apocalyptic number.

It is an amenable number.

14402312325521 is a deficient number, since it is larger than the sum of its proper divisors (69595231).

14402312325521 is an equidigital number, since it uses as much as digits as its factorization.

14402312325521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69595230.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 14402312325521 its reverse (12552321320441), we get a palindrome (26954633645962).

The spelling of 14402312325521 in words is "fourteen trillion, four hundred two billion, three hundred twelve million, three hundred twenty-five thousand, five hundred twenty-one".

Divisors: 1 207563 69387667 14402312325521