Base | Representation |
---|---|
bin | 1101000110010100110010… |
… | …1101011100100110010001 |
3 | 1212222211212220112122001022 |
4 | 3101211030231130212101 |
5 | 3341431413423404041 |
6 | 50344155252245225 |
7 | 3014350503606311 |
oct | 321451455344621 |
9 | 55884786478038 |
10 | 14402312325521 |
11 | 4652a9392740a |
12 | 1747321310815 |
13 | 806194661633 |
14 | 37b10b78b441 |
15 | 19e98580024b |
hex | d194cb5c991 |
14402312325521 has 4 divisors (see below), whose sum is σ = 14402381920752. Its totient is φ = 14402242730292.
The previous prime is 14402312325503. The next prime is 14402312325559. The reversal of 14402312325521 is 12552321320441.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14402312325521 - 222 = 14402308131217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14402312325581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34486271 + ... + 34901396.
It is an arithmetic number, because the mean of its divisors is an integer number (3600595480188).
Almost surely, 214402312325521 is an apocalyptic number.
It is an amenable number.
14402312325521 is a deficient number, since it is larger than the sum of its proper divisors (69595231).
14402312325521 is an equidigital number, since it uses as much as digits as its factorization.
14402312325521 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69595230.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 14402312325521 its reverse (12552321320441), we get a palindrome (26954633645962).
The spelling of 14402312325521 in words is "fourteen trillion, four hundred two billion, three hundred twelve million, three hundred twenty-five thousand, five hundred twenty-one".
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