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14402312325581 is a prime number
BaseRepresentation
bin1101000110010100110010…
…1101011100100111001101
31212222211212220112122010112
43101211030231130213031
53341431413423404311
650344155252245405
73014350503606425
oct321451455344715
955884786478115
1014402312325581
114652a93927464
121747321310865
1380619466167b
1437b10b78b485
1519e98580028b
hexd194cb5c9cd

14402312325581 has 2 divisors, whose sum is σ = 14402312325582. Its totient is φ = 14402312325580.

The previous prime is 14402312325559. The next prime is 14402312325593. The reversal of 14402312325581 is 18552321320441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10277371635556 + 4124940690025 = 3205834^2 + 2030995^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14402312325581 is a prime.

It is a super-2 number, since 2×144023123255812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14402312325481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201156162790 + 7201156162791.

It is an arithmetic number, because the mean of its divisors is an integer number (7201156162791).

Almost surely, 214402312325581 is an apocalyptic number.

It is an amenable number.

14402312325581 is a deficient number, since it is larger than the sum of its proper divisors (1).

14402312325581 is an equidigital number, since it uses as much as digits as its factorization.

14402312325581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 41.

The spelling of 14402312325581 in words is "fourteen trillion, four hundred two billion, three hundred twelve million, three hundred twenty-five thousand, five hundred eighty-one".